Premium Industrial 3 phase 415 Volt Hydraulic Power Units

At Hydraulic.Online, we offer a range of high-quality, 3-phase electric motor-driven hydraulic power units designed for industrial, commercial, and manufacturing applications.

Key Features:

• Produces up to 140 bar (2,000 psi) of pressure.
• Available 7 flow rates from 2.3 to 16 litres per minute (Lt/min).
• Fully assembled and Powder Coated – just add oil and connect to electricity.
• Built with Heavy Duty Components for dependable, reliable continuous operation.

Available Models:

• 2.3 Lt/min at 140 Bar – 0.55 kW motor, 16-litre tank, with standard accessories.
• 3.0 Lt/min at 140 Bar – 0.55 kW motor, 16-litre tank, with standard accessories.
• 4.0 Lt/min at 140 Bar – 1.1 kW motor, 16-litre tank, with standard accessories.
• 6.0 Lt/min at 140 Bar – 1.5 kW motor, 16-litre tank, with standard accessories.
• 9.0 Lt/min at 140 Bar – 2.2 kW motor, 16-litre tank, with standard accessories.
• 11.0 Lt/min at 140 Bar – 3.0 kW motor, 16-litre tank, with standard accessories.
• 16.0 Lt/min at 140 Bar – 4.0 kW motor, 16-litre tank, with standard accessories.

• Larger oil tanks are available as an Option.

Click here for higher flow Industrial Power Units

Click here For Higher Pressure Industrial Units

Included Accessories:

• 3-phase electric motor, bell housing, drive couplings, and quality gear pump.
• Powder-coated steel tank (blue) with a (white) lid and gasket.
• Pump suction strainer.
• Tank-top oil distribution manifold with pressure relief valve set to 140 bar.
• 200 bar stainless steel liquid-filled pressure gauge.
• 10-micron tank-top oil return filter.
• Filler breather strainer.
• Oil level indicator with built-in temperature monitor.
• All internal hose and connections pre-installed.

Please Note: These Industrial Power Units are Assembled to Order and require a 5 to 10 business days Lead time.

How to Select the Right Hydraulic Power Unit

1. Understanding Flow Rate, Pressure, and Motor Power

• Flow Rate (L/min) – Determines cylinder / actuator speed and or a hydraulic motor's RPM.
• Pressure (Bar/PSI) – Defines the force and or torque generated.
• Power (kW/HP) – The electric motor must meet flow and pressure demands.

Formula: kW = (Flow x Pressure) ÷ (600 x Pump Efficiency)

Example: A flow rate of 10 L/min at 150 bar requires approximately 3.0 kW (assuming 85% pump efficiency).

2. Choosing the Right Pump Type

• Gear Pumps – Compact, cost-effective, reliable, and ideal for moderate pressure applications (30-200 bar).
  All our units use gear pumps.
• Vane Pumps – More efficient and quieter; ideal for smooth, consistent flow.
• Piston Pumps – High efficiency, suitable for high-pressure applications (150-420 bar).

3. Selecting the Correct Pump Displacement

Formula: Displacement (cc/rev) = (Flow Rate in L/min × 1,000) ÷ (Motor RPM)

Example:

• 1,400 RPM motor with 20 Lt/min flow = (20 Lt/min x 1,000) / RPM 1,400 = Pump displacement = 14.3 cc/rev.
• 2,800 RPM motor with 20 Lt/min flow → (20 Lt/min x 1,000) / RPM 2,800 Pump displacement = 7.1 cc/rev.

4. Choosing the Right Tank Size

• Oil storage: The tank should be 2-3 times the flow rate for optimal operation.
• Heat dissipation: Larger tanks help prevent overheating.
• Custom options: Choose from various tank sizes and materials.

Additional System Components

• Return filters & filler breathers – Maintain clean oil for extended system life.
• Suction strainers – Protect the pump from contaminants.
• Oil level & temperature indicators – Prevent overheating or low oil conditions.
• Pressure gauges – Monitor system pressure for easy troubleshooting.

Why Choose Hydraulic.Online?

• High-quality, durable components.
• Fully assembled for quick installation.
• Customisable options to suit your requirements.
• Expert advice to ensure the best power unit for your needs.

Need Assistance?

Contact our expert team today to find the perfect hydraulic power unit for your application.

Our Contact details 07 5563 19782 or 1300 1 HOSES

email sales@mhfgc.com.au

---

Electric Motor Power Requirement Chart

To determine the required electric motor power for your hydraulic pump, use the formula:

kW = (L/min × Bar) ÷ (612 × Efficiency)

For an easy reference, download our full power requirement chart.

---

MM 09/02/2025 all New